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By using a combined amplitude analysis of the $\gamma\gamma\rightarrow D\bar{D}$ and $\gamma\gamma\rightarrow J/\psi\omega$ data, we demonstrate that the $X(3915)$, which is quoted as a $J^{PC}=0^{++}$ state in the Particle Data Group table, is favored by the data to be a $J^{PC}=2^{++}$ state appearing in both channels, which means that the $X(3915)$ and the $X(3930)$ can be regarded as the same $J^{PC}=2^{++}$ state.
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In principle, a coupled-channel Breit-Wigner form is required to make a combined analysis for two channels. However, to compare with the experimental analyses, which analyze different channels separately, an elastic Breit-Wigner form is good enough to illustrate our point
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